196=-16t^2+196(0)

Solution for 196=-16t^2+196(0) equation:

196=-16t^2+196(0)

We move all terms to the left:

196-(-16t^2+196(0))=0

We get rid of parentheses

16t^2-1960+196=0

We add all the numbers together, and all the variables

16t^2-1764=0

a = 16; b = 0; c = -1764;
Δ = b2-4ac
Δ = 02-4·16·(-1764)
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{112896}=336$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-336}{2*16}=\frac{-336}{32}
=-10+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+336}{2*16}=\frac{336}{32}
=10+1/2
$